81494333 has 4 divisors (see below), whose sum is σ = 81704220. Its totient is φ = 81284448.

The previous prime is 81494327. The next prime is 81494339. The reversal of 81494333 is 33349418.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33349418 = 2 ⋅16674709.

It is an interprime number because it is at equal distance from previous prime (81494327) and next prime (81494339).

It can be written as a sum of positive squares in 2 ways, for example, as 14303524 + 67190809 = 3782^2 + 8197^2 .

It is a cyclic number.

It is not a de Polignac number, because 81494333 - 2⁶ = 81494269 is a prime.

It is a super-2 number, since 2×81494333² = 13282652622229778, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 81494293 and 81494302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (81494339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 104360 + ... + 105137.

It is an arithmetic number, because the mean of its divisors is an integer number (20426055).

Almost surely, 2^81494333 is an apocalyptic number.

It is an amenable number.

81494333 is a deficient number, since it is larger than the sum of its proper divisors (209887).

81494333 is a wasteful number, since it uses less digits than its factorization.

81494333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209886.

The product of its digits is 31104, while the sum is 35.

The square root of 81494333 is about 9027.4211710765. The cubic root of 81494333 is about 433.5532736880.

The spelling of 81494333 in words is "eighty-one million, four hundred ninety-four thousand, three hundred thirty-three".