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815364031997 is a prime number
BaseRepresentation
bin10111101110101110111…
…10111100010111111101
32212221121010021102200202
423313113132330113331
5101324331143010442
61422323440533245
7112623323630144
oct13672736742775
92787533242622
10815364031997
112948808153a9
12112033921225
135bb72052778
142b66ca6a75b
1516322062c32
hexbdd77bc5fd

815364031997 has 2 divisors, whose sum is σ = 815364031998. Its totient is φ = 815364031996.

The previous prime is 815364031991. The next prime is 815364032003. The reversal of 815364031997 is 799130463518.

It is a balanced prime because it is at equal distance from previous prime (815364031991) and next prime (815364032003).

It can be written as a sum of positive squares in only one way, i.e., 811992023236 + 3372008761 = 901106^2 + 58069^2 .

It is a cyclic number.

It is not a de Polignac number, because 815364031997 - 24 = 815364031981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (815364031991) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 407682015998 + 407682015999.

It is an arithmetic number, because the mean of its divisors is an integer number (407682015999).

Almost surely, 2815364031997 is an apocalyptic number.

It is an amenable number.

815364031997 is a deficient number, since it is larger than the sum of its proper divisors (1).

815364031997 is an equidigital number, since it uses as much as digits as its factorization.

815364031997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 56.

The spelling of 815364031997 in words is "eight hundred fifteen billion, three hundred sixty-four million, thirty-one thousand, nine hundred ninety-seven".