Base | Representation |
---|---|
bin | 11000001010001010100… |
… | …11110000111010011111 |
3 | 2221100121111121011210221 |
4 | 30011011103300322133 |
5 | 102100011410401434 |
6 | 1433201101342211 |
7 | 113654304210223 |
oct | 14050523607237 |
9 | 2840544534727 |
10 | 830091497119 |
11 | 2a0049011985 |
12 | 114a63b67967 |
13 | 6037b298c81 |
14 | 2c2689ca783 |
15 | 168d4e912b4 |
hex | c1454f0e9f |
830091497119 has 2 divisors, whose sum is σ = 830091497120. Its totient is φ = 830091497118.
The previous prime is 830091497117. The next prime is 830091497159. The reversal of 830091497119 is 911794190038.
830091497119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 830091497119 - 21 = 830091497117 is a prime.
It is a super-2 number, since 2×8300914971192 (a number of 25 digits) contains 22 as substring.
Together with 830091497117, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (830091497117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 415045748559 + 415045748560.
It is an arithmetic number, because the mean of its divisors is an integer number (415045748560).
Almost surely, 2830091497119 is an apocalyptic number.
830091497119 is a deficient number, since it is larger than the sum of its proper divisors (1).
830091497119 is an equidigital number, since it uses as much as digits as its factorization.
830091497119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 52.
The spelling of 830091497119 in words is "eight hundred thirty billion, ninety-one million, four hundred ninety-seven thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •