Base | Representation |
---|---|
bin | 10010111001100111011101… |
… | …000100110101110010110110 |
3 | 101220022121010012020121210221 |
4 | 102321213131010311302312 |
5 | 41343401341021110032 |
6 | 452442422503204554 |
7 | 23336345304324553 |
oct | 2271473504656266 |
9 | 356277105217727 |
10 | 83124211113142 |
11 | 24538864147631 |
12 | 93a604214675a |
13 | 374c76c1465b4 |
14 | 167533a1bda2a |
15 | 9923b8baa597 |
hex | 4b99dd135cb6 |
83124211113142 has 16 divisors (see below), whose sum is σ = 130107940841952. Its totient is φ = 39754910831680.
The previous prime is 83124211113067. The next prime is 83124211113149. The reversal of 83124211113142 is 24131111242138.
It is a super-3 number, since 3×831242111131423 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 83124211113098 and 83124211113107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (83124211113149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9830892 + ... + 16214032.
It is an arithmetic number, because the mean of its divisors is an integer number (8131746302622).
Almost surely, 283124211113142 is an apocalyptic number.
83124211113142 is a deficient number, since it is larger than the sum of its proper divisors (46983729728810).
83124211113142 is a wasteful number, since it uses less digits than its factorization.
83124211113142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6666263.
The product of its digits is 9216, while the sum is 34.
The spelling of 83124211113142 in words is "eighty-three trillion, one hundred twenty-four billion, two hundred eleven million, one hundred thirteen thousand, one hundred forty-two".
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