Base | Representation |
---|---|
bin | 100110101101011111… |
… | …1100111101000110011 |
3 | 21221120112122122002022 |
4 | 1031122333213220303 |
5 | 2330223014133431 |
6 | 102105001542055 |
7 | 6002030613332 |
oct | 1153277475063 |
9 | 257515578068 |
10 | 83131005491 |
11 | 3228a315926 |
12 | 141404a492b |
13 | 7aba9c76a1 |
14 | 4048923d19 |
15 | 22682de07b |
hex | 135afe7a33 |
83131005491 has 2 divisors, whose sum is σ = 83131005492. Its totient is φ = 83131005490.
The previous prime is 83131005469. The next prime is 83131005493. The reversal of 83131005491 is 19450013138.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 83131005491 - 218 = 83130743347 is a prime.
Together with 83131005493, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (83131005493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41565502745 + 41565502746.
It is an arithmetic number, because the mean of its divisors is an integer number (41565502746).
Almost surely, 283131005491 is an apocalyptic number.
83131005491 is a deficient number, since it is larger than the sum of its proper divisors (1).
83131005491 is an equidigital number, since it uses as much as digits as its factorization.
83131005491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 83131005491 in words is "eighty-three billion, one hundred thirty-one million, five thousand, four hundred ninety-one".
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