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83651343749 is a prime number
BaseRepresentation
bin100110111101000000…
…0100011010110000101
321222220210202112222122
41031322000203112011
52332304220444444
6102232350335325
76020646455441
oct1157200432605
9258823675878
1083651343749
1132527003746
12142667ba545
137b71750b4c
144097a91821
152298d234ee
hex137a023585

83651343749 has 2 divisors, whose sum is σ = 83651343750. Its totient is φ = 83651343748.

The previous prime is 83651343707. The next prime is 83651343791. The reversal of 83651343749 is 94734315638.

It is a balanced prime because it is at equal distance from previous prime (83651343707) and next prime (83651343791).

It can be written as a sum of positive squares in only one way, i.e., 82401721249 + 1249622500 = 287057^2 + 35350^2 .

It is a cyclic number.

It is not a de Polignac number, because 83651343749 - 216 = 83651278213 is a prime.

It is a super-2 number, since 2×836513437492 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 83651343749.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (83651343049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41825671874 + 41825671875.

It is an arithmetic number, because the mean of its divisors is an integer number (41825671875).

Almost surely, 283651343749 is an apocalyptic number.

It is an amenable number.

83651343749 is a deficient number, since it is larger than the sum of its proper divisors (1).

83651343749 is an equidigital number, since it uses as much as digits as its factorization.

83651343749 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6531840, while the sum is 53.

The spelling of 83651343749 in words is "eighty-three billion, six hundred fifty-one million, three hundred forty-three thousand, seven hundred forty-nine".