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84120000000 = 29357701
BaseRepresentation
bin100111001010111110…
…0010101011000000000
322001010110121202111120
41032111330111120000
52334234210000000
6102351051312240
76035400126261
oct1162574253000
9261113552446
1084120000000
1132747602063
121437774b680
137c1788043a
144100008968
1522c50496a0
hex1395f15600

84120000000 has 320 divisors, whose sum is σ = 280525063104. Its totient is φ = 22400000000.

The previous prime is 84119999993. The next prime is 84120000011. The reversal of 84120000000 is 2148.

It is a tau number, because it is divible by the number of its divisors (320).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 119999650 + ... + 120000350.

Almost surely, 284120000000 is an apocalyptic number.

84120000000 is a gapful number since it is divisible by the number (80) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 84120000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (140262531552).

84120000000 is an abundant number, since it is smaller than the sum of its proper divisors (196405063104).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

84120000000 is an frugal number, since it uses more digits than its factorization.

84120000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 757 (or 711 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 15.

Adding to 84120000000 its reverse (2148), we get a palindrome (84120002148).

The spelling of 84120000000 in words is "eighty-four billion, one hundred twenty million", and thus it is an aban number.