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8492001437 is a prime number
BaseRepresentation
bin1111110100010100…
…11010100010011101
3210220211012100222202
413322022122202131
5114342423021222
63522353021245
7420303551453
oct77212324235
923824170882
108492001437
113668571407
12178bb54825
13a5445762a
145a7b7a9d3
1534a7d3892
hex1fa29a89d

8492001437 has 2 divisors, whose sum is σ = 8492001438. Its totient is φ = 8492001436.

The previous prime is 8492001433. The next prime is 8492001439. The reversal of 8492001437 is 7341002948.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7566564196 + 925437241 = 86986^2 + 30421^2 .

It is a cyclic number.

It is not a de Polignac number, because 8492001437 - 22 = 8492001433 is a prime.

It is a super-2 number, since 2×84920014372 (a number of 21 digits) contains 22 as substring.

Together with 8492001439, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 8492001437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8492001433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4246000718 + 4246000719.

It is an arithmetic number, because the mean of its divisors is an integer number (4246000719).

Almost surely, 28492001437 is an apocalyptic number.

It is an amenable number.

8492001437 is a deficient number, since it is larger than the sum of its proper divisors (1).

8492001437 is an equidigital number, since it uses as much as digits as its factorization.

8492001437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 38.

The square root of 8492001437 is about 92152.0560649625. The cubic root of 8492001437 is about 2040.1872054428.

The spelling of 8492001437 in words is "eight billion, four hundred ninety-two million, one thousand, four hundred thirty-seven".