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852092634317 is a prime number
BaseRepresentation
bin11000110011001001010…
…11011100010011001101
310000110101210121202020012
430121210223130103031
5102430041203244232
61451240154203005
7115363435613321
oct14314453342315
93013353552205
10852092634317
112a94090949a1
12119184123465
1362476428752
142d354985981
15172717469b2
hexc664adc4cd

852092634317 has 2 divisors, whose sum is σ = 852092634318. Its totient is φ = 852092634316.

The previous prime is 852092634293. The next prime is 852092634319. The reversal of 852092634317 is 713436290258.

852092634317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 553693739236 + 298398895081 = 744106^2 + 546259^2 .

It is a cyclic number.

It is not a de Polignac number, because 852092634317 - 228 = 851824198861 is a prime.

Together with 852092634319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (852092634319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 426046317158 + 426046317159.

It is an arithmetic number, because the mean of its divisors is an integer number (426046317159).

It is a 1-persistent number, because it is pandigital, but 2⋅852092634317 = 1704185268634 is not.

Almost surely, 2852092634317 is an apocalyptic number.

It is an amenable number.

852092634317 is a deficient number, since it is larger than the sum of its proper divisors (1).

852092634317 is an equidigital number, since it uses as much as digits as its factorization.

852092634317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 50.

The spelling of 852092634317 in words is "eight hundred fifty-two billion, ninety-two million, six hundred thirty-four thousand, three hundred seventeen".