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857065431253 is a prime number
BaseRepresentation
bin11000111100011010001…
…01001010000011010101
310000221020100211000012111
430132031011022003111
5103020232222300003
61453421434351021
7115630610651503
oct14361505120325
93027210730174
10857065431253
11300530101929
1211a13158b471
1362a89751445
142d6a71a5673
15174630c7e6d
hexc78d14a0d5

857065431253 has 2 divisors, whose sum is σ = 857065431254. Its totient is φ = 857065431252.

The previous prime is 857065431241. The next prime is 857065431301. The reversal of 857065431253 is 352134560758.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 754045616164 + 103019815089 = 868358^2 + 320967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-857065431253 is a prime.

It is a super-2 number, since 2×8570654312532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 857065431197 and 857065431206.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (857065437253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 428532715626 + 428532715627.

It is an arithmetic number, because the mean of its divisors is an integer number (428532715627).

Almost surely, 2857065431253 is an apocalyptic number.

It is an amenable number.

857065431253 is a deficient number, since it is larger than the sum of its proper divisors (1).

857065431253 is an equidigital number, since it uses as much as digits as its factorization.

857065431253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024000, while the sum is 49.

The spelling of 857065431253 in words is "eight hundred fifty-seven billion, sixty-five million, four hundred thirty-one thousand, two hundred fifty-three".