Search a number
-
+
893243541941 is a prime number
BaseRepresentation
bin11001111111110010111…
…01101100100110110101
310011101121200022110011222
430333321131230212311
5104113330321320231
61522203405040125
7121351256555042
oct14777135544665
93141550273158
10893243541941
11314905768963
12125149556045
1366303a7422a
1431339d441c9
151837e2bd27b
hexcff976c9b5

893243541941 has 2 divisors, whose sum is σ = 893243541942. Its totient is φ = 893243541940.

The previous prime is 893243541923. The next prime is 893243541959. The reversal of 893243541941 is 149145342398.

It is a balanced prime because it is at equal distance from previous prime (893243541923) and next prime (893243541959).

It can be written as a sum of positive squares in only one way, i.e., 793684992100 + 99558549841 = 890890^2 + 315529^2 .

It is a cyclic number.

It is not a de Polignac number, because 893243541941 - 26 = 893243541877 is a prime.

It is a super-5 number, since 5×8932435419415 (a number of 61 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (893243541901) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 446621770970 + 446621770971.

It is an arithmetic number, because the mean of its divisors is an integer number (446621770971).

Almost surely, 2893243541941 is an apocalyptic number.

It is an amenable number.

893243541941 is a deficient number, since it is larger than the sum of its proper divisors (1).

893243541941 is an equidigital number, since it uses as much as digits as its factorization.

893243541941 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3732480, while the sum is 53.

The spelling of 893243541941 in words is "eight hundred ninety-three billion, two hundred forty-three million, five hundred forty-one thousand, nine hundred forty-one".