Base | Representation |
---|---|
bin | 101001101101000001… |
… | …1010100100000111111 |
3 | 22120011102111222021102 |
4 | 1103122003110200333 |
5 | 2431403224240341 |
6 | 105050415123315 |
7 | 6320215313603 |
oct | 1233203244077 |
9 | 276142458242 |
10 | 89557649471 |
11 | 34a87a5a644 |
12 | 1543481353b |
13 | 85a32a32c4 |
14 | 4498271503 |
15 | 24e25eec9b |
hex | 14da0d483f |
89557649471 has 2 divisors, whose sum is σ = 89557649472. Its totient is φ = 89557649470.
The previous prime is 89557649431. The next prime is 89557649473. The reversal of 89557649471 is 17494675598.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 89557649471 - 210 = 89557648447 is a prime.
It is a super-3 number, since 3×895576494713 (a number of 34 digits) contains 333 as substring.
Together with 89557649473, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 89557649398 and 89557649407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (89557649473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44778824735 + 44778824736.
It is an arithmetic number, because the mean of its divisors is an integer number (44778824736).
Almost surely, 289557649471 is an apocalyptic number.
89557649471 is a deficient number, since it is larger than the sum of its proper divisors (1).
89557649471 is an equidigital number, since it uses as much as digits as its factorization.
89557649471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 76204800, while the sum is 65.
The spelling of 89557649471 in words is "eighty-nine billion, five hundred fifty-seven million, six hundred forty-nine thousand, four hundred seventy-one".
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