Base | Representation |
---|---|
bin | 10100101100001110010110… |
… | …101011001011000000000011 |
3 | 102221012111220110111200221111 |
4 | 110230032112223023000003 |
5 | 43411421000000000003 |
6 | 521312453424104151 |
7 | 25111350555313663 |
oct | 2454162653130003 |
9 | 387174813450844 |
10 | 91000000000003 |
11 | 26aa49796a9056 |
12 | a2584aba65057 |
13 | 3ba1356286273 |
14 | 18685d012a1a3 |
15 | a7c1bb0e2e6d |
hex | 52c396acb003 |
91000000000003 has 2 divisors, whose sum is σ = 91000000000004. Its totient is φ = 91000000000002.
The previous prime is 90999999999913. The next prime is 91000000000037. The reversal of 91000000000003 is 30000000000019.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 91000000000003 - 245 = 55815627911171 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 90999999999893 and 90999999999902.
It is not a weakly prime, because it can be changed into another prime (91000000000093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45500000000001 + 45500000000002.
It is an arithmetic number, because the mean of its divisors is an integer number (45500000000002).
Almost surely, 291000000000003 is an apocalyptic number.
91000000000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
91000000000003 is an equidigital number, since it uses as much as digits as its factorization.
91000000000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 13.
The spelling of 91000000000003 in words is "ninety-one trillion, three", and thus it is an aban number and an uban number.
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