Base | Representation |
---|---|
bin | 101010011000000001… |
… | …1100100010111111101 |
3 | 22200212222121011120010 |
4 | 1110300003210113331 |
5 | 2442332120230010 |
6 | 105445521413433 |
7 | 6401035645353 |
oct | 1246003442775 |
9 | 280788534503 |
10 | 91000555005 |
11 | 35658493958 |
12 | 15777a9a279 |
13 | 87731c4c69 |
14 | 4593b517d3 |
15 | 257911c620 |
hex | 15300e45fd |
91000555005 has 16 divisors (see below), whose sum is σ = 153264093120. Its totient is φ = 45979227648.
The previous prime is 91000555003. The next prime is 91000555021. The reversal of 91000555005 is 50055500019.
It is not a de Polignac number, because 91000555005 - 21 = 91000555003 is a prime.
It is a super-3 number, since 3×910005550053 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (91000555003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 159649812 + ... + 159650381.
It is an arithmetic number, because the mean of its divisors is an integer number (9579005820).
Almost surely, 291000555005 is an apocalyptic number.
91000555005 is a gapful number since it is divisible by the number (95) formed by its first and last digit.
It is an amenable number.
91000555005 is a deficient number, since it is larger than the sum of its proper divisors (62263538115).
91000555005 is a wasteful number, since it uses less digits than its factorization.
91000555005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319300220.
The product of its (nonzero) digits is 5625, while the sum is 30.
The spelling of 91000555005 in words is "ninety-one billion, five hundred fifty-five thousand, five".
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