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91300620122735 = 5138113222392487
BaseRepresentation
bin10100110000100110010101…
…000001111011101001101111
3102222021020212012022020011012
4110300212111001323221233
543431332132222411420
6522102531552415435
725142152323225332
oct2460462501735157
9388236765266135
1091300620122735
1127100414947781
12a2a6808b4757b
133bc37c47079aa
141878d8b772619
15a84e12e46dc5
hex53099507ba6f

91300620122735 has 8 divisors (see below), whose sum is σ = 109640078510496. Its totient is φ = 72987606522720.

The previous prime is 91300620122729. The next prime is 91300620122737. The reversal of 91300620122735 is 53722102600319.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 91300620122735 - 26 = 91300620122671 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 91300620122692 and 91300620122701.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (91300620122737) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6611189339 + ... + 6611203148.

It is an arithmetic number, because the mean of its divisors is an integer number (13705009813812).

Almost surely, 291300620122735 is an apocalyptic number.

91300620122735 is a deficient number, since it is larger than the sum of its proper divisors (18339458387761).

91300620122735 is a wasteful number, since it uses less digits than its factorization.

91300620122735 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13222393873.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 91300620122735 in words is "ninety-one trillion, three hundred billion, six hundred twenty million, one hundred twenty-two thousand, seven hundred thirty-five".

Divisors: 1 5 1381 6905 13222392487 66111962435 18260124024547 91300620122735