Base | Representation |
---|---|
bin | 101010100011100110… |
… | …0101010010011010111 |
3 | 22201220001011210112022 |
4 | 1111013030222103113 |
5 | 2444131014031201 |
6 | 105552231243355 |
7 | 6413462051366 |
oct | 1250714522327 |
9 | 281801153468 |
10 | 91388814551 |
11 | 35837670011 |
12 | 15865b1955b |
13 | 8805785738 |
14 | 45cd53b7dd |
15 | 259d26241b |
hex | 154732a4d7 |
91388814551 has 2 divisors, whose sum is σ = 91388814552. Its totient is φ = 91388814550.
The previous prime is 91388814529. The next prime is 91388814553. The reversal of 91388814551 is 15541888319.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-91388814551 is a prime.
Together with 91388814553, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 91388814493 and 91388814502.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (91388814553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45694407275 + 45694407276.
It is an arithmetic number, because the mean of its divisors is an integer number (45694407276).
Almost surely, 291388814551 is an apocalyptic number.
91388814551 is a deficient number, since it is larger than the sum of its proper divisors (1).
91388814551 is an equidigital number, since it uses as much as digits as its factorization.
91388814551 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1382400, while the sum is 53.
The spelling of 91388814551 in words is "ninety-one billion, three hundred eighty-eight million, eight hundred fourteen thousand, five hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •