Base | Representation |
---|---|
bin | 101011010111010111… |
… | …0001010111010101111 |
3 | 22220101002100021210112 |
4 | 1112232232022322233 |
5 | 3011210131332033 |
6 | 110440433530235 |
7 | 6504511661006 |
oct | 1265656127257 |
9 | 286332307715 |
10 | 93125652143 |
11 | 36549003887 |
12 | 1606b71397b |
13 | 8a2155c2a4 |
14 | 4716091c3d |
15 | 2650990c48 |
hex | 15aeb8aeaf |
93125652143 has 2 divisors, whose sum is σ = 93125652144. Its totient is φ = 93125652142.
The previous prime is 93125652133. The next prime is 93125652149. The reversal of 93125652143 is 34125652139.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 93125652143 - 24 = 93125652127 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 93125652143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (93125652149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46562826071 + 46562826072.
It is an arithmetic number, because the mean of its divisors is an integer number (46562826072).
Almost surely, 293125652143 is an apocalyptic number.
93125652143 is a deficient number, since it is larger than the sum of its proper divisors (1).
93125652143 is an equidigital number, since it uses as much as digits as its factorization.
93125652143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 194400, while the sum is 41.
The spelling of 93125652143 in words is "ninety-three billion, one hundred twenty-five million, six hundred fifty-two thousand, one hundred forty-three".
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