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93253066631111 is a prime number
BaseRepresentation
bin10101001101000000101011…
…111010010010011111000111
3110020011220110112212102001202
4111031000223322102133013
544210324240024143421
6530155511205213115
725433211631560212
oct2515005372223707
9406156415772052
1093253066631111
1127793449013462
12a56109b40119b
13400595a02002a
1419056887ba779
15abaad624110b
hex54d02be927c7

93253066631111 has 2 divisors, whose sum is σ = 93253066631112. Its totient is φ = 93253066631110.

The previous prime is 93253066631093. The next prime is 93253066631113. The reversal of 93253066631111 is 11113666035239.

It is a strong prime.

It is an emirp because it is prime and its reverse (11113666035239) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 93253066631111 - 26 = 93253066631047 is a prime.

It is a super-2 number, since 2×932530666311112 (a number of 29 digits) contains 22 as substring.

Together with 93253066631113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (93253066631113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46626533315555 + 46626533315556.

It is an arithmetic number, because the mean of its divisors is an integer number (46626533315556).

Almost surely, 293253066631111 is an apocalyptic number.

93253066631111 is a deficient number, since it is larger than the sum of its proper divisors (1).

93253066631111 is an equidigital number, since it uses as much as digits as its factorization.

93253066631111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 47.

The spelling of 93253066631111 in words is "ninety-three trillion, two hundred fifty-three billion, sixty-six million, six hundred thirty-one thousand, one hundred eleven".