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93280000000 = 211571153
BaseRepresentation
bin101011011011111101…
…0111101100000000000
322220202211202222020211
41112313322331200000
53012014140000000
6110504030043504
76511364626525
oct1266772754000
9286684688224
1093280000000
11366181456a0
12160b3349594
138a47521195
14472c78d14c
15265e2cd7ba
hex15b7ebd800

93280000000 has 384 divisors, whose sum is σ = 259136055360. Its totient is φ = 33280000000.

The previous prime is 93279999959. The next prime is 93280000001. The reversal of 93280000000 is 8239.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (93280000001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1759999974 + ... + 1760000026.

Almost surely, 293280000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 93280000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (129568027680).

93280000000 is an abundant number, since it is smaller than the sum of its proper divisors (165856055360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

93280000000 is an frugal number, since it uses more digits than its factorization.

93280000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121 (or 71 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 93280000000 its reverse (8239), we get a palindrome (93280008239).

The spelling of 93280000000 in words is "ninety-three billion, two hundred eighty million", and thus it is an aban number.