Base | Representation |
---|---|
bin | 10101010100000011110010… |
… | …010100110100101110001000 |
3 | 110021220012200210102001212211 |
4 | 111110003302110310232020 |
5 | 44241243230021004000 |
6 | 531210214240114504 |
7 | 25513206641644513 |
oct | 2524036224645610 |
9 | 407805623361784 |
10 | 93737431813000 |
11 | 2795a90458a678 |
12 | a61ab38305a34 |
13 | 403c52bc55131 |
14 | 1920cb736bd7a |
15 | ac84d44657ba |
hex | 5540f2534b88 |
93737431813000 has 64 divisors (see below), whose sum is σ = 226421254725120. Its totient is φ = 36285457464000.
The previous prime is 93737431812943. The next prime is 93737431813061. The reversal of 93737431813000 is 31813473739.
93737431813000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×937374318130002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1511863062 + ... + 1511925061.
It is an arithmetic number, because the mean of its divisors is an integer number (3537832105080).
Almost surely, 293737431813000 is an apocalyptic number.
It is an amenable number.
93737431813000 is an abundant number, since it is smaller than the sum of its proper divisors (132683822912120).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
93737431813000 is a wasteful number, since it uses less digits than its factorization.
93737431813000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3023788175 (or 3023788161 counting only the distinct ones).
The product of its (nonzero) digits is 1143072, while the sum is 49.
The spelling of 93737431813000 in words is "ninety-three trillion, seven hundred thirty-seven billion, four hundred thirty-one million, eight hundred thirteen thousand".
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