93941213 has 2 divisors, whose sum is σ = 93941214. Its totient is φ = 93941212.

The previous prime is 93941147. The next prime is 93941273. The reversal of 93941213 is 31214939.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89832484 + 4108729 = 9478^2 + 2027^2 .

It is a cyclic number.

It is not a de Polignac number, because 93941213 - 2¹⁴ = 93924829 is a prime.

It is a super-2 number, since 2×93941213² = 17649902999822738, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 93941213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (93941273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46970606 + 46970607.

It is an arithmetic number, because the mean of its divisors is an integer number (46970607).

Almost surely, 2^93941213 is an apocalyptic number.

It is an amenable number.

93941213 is a deficient number, since it is larger than the sum of its proper divisors (1).

93941213 is an equidigital number, since it uses as much as digits as its factorization.

93941213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5832, while the sum is 32.

The square root of 93941213 is about 9692.3275326415. The cubic root of 93941213 is about 454.5887892055.

The spelling of 93941213 in words is "ninety-three million, nine hundred forty-one thousand, two hundred thirteen".