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94091219953 is a prime number
BaseRepresentation
bin101011110100001000…
…1100001001111110001
322222212101020012211021
41113220101201033301
53020144323014303
6111120325215441
76540445113343
oct1275021411761
9288771205737
1094091219953
11369a404a205
121629ab61581
138b46601ca3
1447a83d9293
1526aa61eebd
hex15e84613f1

94091219953 has 2 divisors, whose sum is σ = 94091219954. Its totient is φ = 94091219952.

The previous prime is 94091219951. The next prime is 94091220017. The reversal of 94091219953 is 35991219049.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 48972362209 + 45118857744 = 221297^2 + 212412^2 .

It is an emirp because it is prime and its reverse (35991219049) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 94091219953 - 21 = 94091219951 is a prime.

Together with 94091219951, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 94091219953.

It is not a weakly prime, because it can be changed into another prime (94091219951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47045609976 + 47045609977.

It is an arithmetic number, because the mean of its divisors is an integer number (47045609977).

Almost surely, 294091219953 is an apocalyptic number.

It is an amenable number.

94091219953 is a deficient number, since it is larger than the sum of its proper divisors (1).

94091219953 is an equidigital number, since it uses as much as digits as its factorization.

94091219953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 787320, while the sum is 52.

The spelling of 94091219953 in words is "ninety-four billion, ninety-one million, two hundred nineteen thousand, nine hundred fifty-three".