Base | Representation |
---|---|
bin | 101011110100001000… |
… | …1100001001111101111 |
3 | 22222212101020012211012 |
4 | 1113220101201033233 |
5 | 3020144323014301 |
6 | 111120325215435 |
7 | 6540445113341 |
oct | 1275021411757 |
9 | 288771205735 |
10 | 94091219951 |
11 | 369a404a203 |
12 | 1629ab6157b |
13 | 8b46601ca1 |
14 | 47a83d9291 |
15 | 26aa61eebb |
hex | 15e84613ef |
94091219951 has 2 divisors, whose sum is σ = 94091219952. Its totient is φ = 94091219950.
The previous prime is 94091219939. The next prime is 94091219953. The reversal of 94091219951 is 15991219049.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-94091219951 is a prime.
Together with 94091219953, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 94091219951.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (94091219953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47045609975 + 47045609976.
It is an arithmetic number, because the mean of its divisors is an integer number (47045609976).
Almost surely, 294091219951 is an apocalyptic number.
94091219951 is a deficient number, since it is larger than the sum of its proper divisors (1).
94091219951 is an equidigital number, since it uses as much as digits as its factorization.
94091219951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 262440, while the sum is 50.
The spelling of 94091219951 in words is "ninety-four billion, ninety-one million, two hundred nineteen thousand, nine hundred fifty-one".
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