Base | Representation |
---|---|
bin | 101100011100010101… |
… | …1110011001001101101 |
3 | 100010100101201212222011 |
4 | 1120320223303021231 |
5 | 3030430203130232 |
6 | 111502240321221 |
7 | 6616046022415 |
oct | 1307053631155 |
9 | 303311655864 |
10 | 95440286317 |
11 | 3752660a792 |
12 | 165b6913211 |
13 | 8cccc593cc |
14 | 489564d645 |
15 | 2738ca3547 |
hex | 1638af326d |
95440286317 has 2 divisors, whose sum is σ = 95440286318. Its totient is φ = 95440286316.
The previous prime is 95440286287. The next prime is 95440286323. The reversal of 95440286317 is 71368204459.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 62393045796 + 33047240521 = 249786^2 + 181789^2 .
It is a cyclic number.
It is not a de Polignac number, because 95440286317 - 215 = 95440253549 is a prime.
It is a congruent number.
It is a weakly prime.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47720143158 + 47720143159.
It is an arithmetic number, because the mean of its divisors is an integer number (47720143159).
It is a 2-persistent number, because it is pandigital, and so is 2⋅95440286317 = 190880572634, but 3⋅95440286317 = 286320858951 is not.
Almost surely, 295440286317 is an apocalyptic number.
It is an amenable number.
95440286317 is a deficient number, since it is larger than the sum of its proper divisors (1).
95440286317 is an equidigital number, since it uses as much as digits as its factorization.
95440286317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 49.
The spelling of 95440286317 in words is "ninety-five billion, four hundred forty million, two hundred eighty-six thousand, three hundred seventeen".
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