Search a number
-
+
96000000000053 is a prime number
BaseRepresentation
bin10101110100111110111101…
…111001100000000000110101
3110120220111210001121211102112
4111310332331321200000311
5100040331000000000203
6540101442520420405
726135525331136232
oct2564767571400065
9416814701554375
1096000000000053
112865240a315656
12a925539917705
1341749b834a556
14199c5d38b2789
15b172a88146d8
hex574fbde60035

96000000000053 has 2 divisors, whose sum is σ = 96000000000054. Its totient is φ = 96000000000052.

The previous prime is 95999999999999. The next prime is 96000000000167. The reversal of 96000000000053 is 35000000000069.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93312161071684 + 2687838928369 = 9659822^2 + 1639463^2 .

It is a cyclic number.

It is not a de Polignac number, because 96000000000053 - 26 = 95999999999989 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 95999999999938 and 96000000000028.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96000000000953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48000000000026 + 48000000000027.

It is an arithmetic number, because the mean of its divisors is an integer number (48000000000027).

Almost surely, 296000000000053 is an apocalyptic number.

It is an amenable number.

96000000000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

96000000000053 is an equidigital number, since it uses as much as digits as its factorization.

96000000000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 810, while the sum is 23.

The spelling of 96000000000053 in words is "ninety-six trillion, fifty-three", and thus it is an aban number and an uban number.