Base | Representation |
---|---|
bin | 101101001110110101… |
… | …0111101001100011111 |
3 | 100021201110211010012011 |
4 | 1122131222331030133 |
5 | 3042412422023002 |
6 | 112342322452051 |
7 | 10006041113026 |
oct | 1323552751437 |
9 | 307643733164 |
10 | 97134564127 |
11 | 38215a24787 |
12 | 169aa204027 |
13 | 920cc81263 |
14 | 49b66858bd |
15 | 27d78c68d7 |
hex | 169dabd31f |
97134564127 has 2 divisors, whose sum is σ = 97134564128. Its totient is φ = 97134564126.
The previous prime is 97134564119. The next prime is 97134564157. The reversal of 97134564127 is 72146543179.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 97134564127 - 23 = 97134564119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97134564157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48567282063 + 48567282064.
It is an arithmetic number, because the mean of its divisors is an integer number (48567282064).
Almost surely, 297134564127 is an apocalyptic number.
97134564127 is a deficient number, since it is larger than the sum of its proper divisors (1).
97134564127 is an equidigital number, since it uses as much as digits as its factorization.
97134564127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1270080, while the sum is 49.
The spelling of 97134564127 in words is "ninety-seven billion, one hundred thirty-four million, five hundred sixty-four thousand, one hundred twenty-seven".
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