Base | Representation |
---|---|
bin | 10110000110111100111110… |
… | …000101101100111110010111 |
3 | 110202021120000211111222222112 |
4 | 112012330332011230332113 |
5 | 100221043340402441341 |
6 | 542445015305021235 |
7 | 26323661100364154 |
oct | 2606747605547627 |
9 | 422246024458875 |
10 | 97234806296471 |
11 | 28a89060280378 |
12 | aaa490ba8481b |
13 | 423428399780c |
14 | 1a022928c322b |
15 | b3947906baeb |
hex | 586f3e16cf97 |
97234806296471 has 2 divisors, whose sum is σ = 97234806296472. Its totient is φ = 97234806296470.
The previous prime is 97234806296447. The next prime is 97234806296519. The reversal of 97234806296471 is 17469260843279.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 97234806296471 - 210 = 97234806295447 is a prime.
It is a super-3 number, since 3×972348062964713 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97234806296371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48617403148235 + 48617403148236.
It is an arithmetic number, because the mean of its divisors is an integer number (48617403148236).
Almost surely, 297234806296471 is an apocalyptic number.
97234806296471 is a deficient number, since it is larger than the sum of its proper divisors (1).
97234806296471 is an equidigital number, since it uses as much as digits as its factorization.
97234806296471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 219469824, while the sum is 68.
The spelling of 97234806296471 in words is "ninety-seven trillion, two hundred thirty-four billion, eight hundred six million, two hundred ninety-six thousand, four hundred seventy-one".
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