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973909000541 is a prime number
BaseRepresentation
bin11100010110000011000…
…00000000000101011101
310110002211101121022202202
432023001200000011131
5111424031201004131
62023224013501245
7130235241626141
oct16130140000535
93402741538682
10973909000541
1134603a271924
121389001a1825
1370abaa13319
14351cd225221
151a500dd9bcb
hexe2c180015d

973909000541 has 2 divisors, whose sum is σ = 973909000542. Its totient is φ = 973909000540.

The previous prime is 973909000517. The next prime is 973909000543. The reversal of 973909000541 is 145000909379.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 954878798041 + 19030202500 = 977179^2 + 137950^2 .

It is an emirp because it is prime and its reverse (145000909379) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 973909000541 - 214 = 973908984157 is a prime.

Together with 973909000543, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (973909000543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 486954500270 + 486954500271.

It is an arithmetic number, because the mean of its divisors is an integer number (486954500271).

Almost surely, 2973909000541 is an apocalyptic number.

It is an amenable number.

973909000541 is a deficient number, since it is larger than the sum of its proper divisors (1).

973909000541 is an equidigital number, since it uses as much as digits as its factorization.

973909000541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 306180, while the sum is 47.

The spelling of 973909000541 in words is "nine hundred seventy-three billion, nine hundred nine million, five hundred forty-one", and thus it is an aban number.