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980352031103 is a prime number
BaseRepresentation
bin11100100010000011000…
…10001101100101111111
310110201110102022012010022
432101001202031211333
5112030230104443403
62030211214202355
7130554015525614
oct16210142154577
93421412265108
10980352031103
11348846189075
12139bb9ab33bb
13715a6808743
1435640bda50b
151a77b885d38
hexe44188d97f

980352031103 has 2 divisors, whose sum is σ = 980352031104. Its totient is φ = 980352031102.

The previous prime is 980352031097. The next prime is 980352031111. The reversal of 980352031103 is 301130253089.

It is a happy number.

980352031103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (301130253089) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 980352031103 - 210 = 980352030079 is a prime.

It is a super-2 number, since 2×9803520311032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (980352031003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490176015551 + 490176015552.

It is an arithmetic number, because the mean of its divisors is an integer number (490176015552).

Almost surely, 2980352031103 is an apocalyptic number.

980352031103 is a deficient number, since it is larger than the sum of its proper divisors (1).

980352031103 is an equidigital number, since it uses as much as digits as its factorization.

980352031103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 980352031103 in words is "nine hundred eighty billion, three hundred fifty-two million, thirty-one thousand, one hundred three".