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98103434797 is a prime number
BaseRepresentation
bin101101101011101101…
…0111001111000101101
3100101012222220211220001
41123113122321320231
53101403434403142
6113022413024301
710042044302614
oct1332732717055
9311188824801
1098103434797
1138672916645
121701a785091
13933590c404
144a6920c87b
1528429a95b7
hex16d76b9e2d

98103434797 has 2 divisors, whose sum is σ = 98103434798. Its totient is φ = 98103434796.

The previous prime is 98103434747. The next prime is 98103434843. The reversal of 98103434797 is 79743430189.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57453213636 + 40650221161 = 239694^2 + 201619^2 .

It is an emirp because it is prime and its reverse (79743430189) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 98103434797 - 219 = 98102910509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98103434717) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49051717398 + 49051717399.

It is an arithmetic number, because the mean of its divisors is an integer number (49051717399).

Almost surely, 298103434797 is an apocalyptic number.

It is an amenable number.

98103434797 is a deficient number, since it is larger than the sum of its proper divisors (1).

98103434797 is an equidigital number, since it uses as much as digits as its factorization.

98103434797 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4572288, while the sum is 55.

It can be divided in two parts, 98103 and 434797, that added together give a square (532900 = 7302).

The spelling of 98103434797 in words is "ninety-eight billion, one hundred three million, four hundred thirty-four thousand, seven hundred ninety-seven".