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981481253 is a prime number
BaseRepresentation
bin111010100000000…
…011011100100101
32112101211102011112
4322200003130211
54002224400003
6241220314405
733215311244
oct7240033445
92471742145
10981481253
11464025435
12234842a05
1312845504c
14944ca95b
155b2743d8
hex3a803725

981481253 has 2 divisors, whose sum is σ = 981481254. Its totient is φ = 981481252.

The previous prime is 981481219. The next prime is 981481301. The reversal of 981481253 is 352184189.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 974501089 + 6980164 = 31217^2 + 2642^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-981481253 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 981481253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (981481153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490740626 + 490740627.

It is an arithmetic number, because the mean of its divisors is an integer number (490740627).

Almost surely, 2981481253 is an apocalyptic number.

It is an amenable number.

981481253 is a deficient number, since it is larger than the sum of its proper divisors (1).

981481253 is an equidigital number, since it uses as much as digits as its factorization.

981481253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 69120, while the sum is 41.

The square root of 981481253 is about 31328.6011976277. The cubic root of 981481253 is about 993.7885825084.

The spelling of 981481253 in words is "nine hundred eighty-one million, four hundred eighty-one thousand, two hundred fifty-three".