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9881422501217 is a prime number
BaseRepresentation
bin1000111111001011001010…
…1011011001010101100001
31021222122200022202012011012
42033302302223121111201
52243344123130014332
633003243545430305
72036623601261621
oct217626253312541
937878608665135
109881422501217
11316a762437143
12113710449b395
13568a7789a667
14262398ab4881
15122089cc93b2
hex8fcb2ad9561

9881422501217 has 2 divisors, whose sum is σ = 9881422501218. Its totient is φ = 9881422501216.

The previous prime is 9881422501199. The next prime is 9881422501219. The reversal of 9881422501217 is 7121052241889.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6343829540416 + 3537592960801 = 2518696^2 + 1880849^2 .

It is a cyclic number.

It is not a de Polignac number, because 9881422501217 - 234 = 9864242632033 is a prime.

Together with 9881422501219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (9881422501219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4940711250608 + 4940711250609.

It is an arithmetic number, because the mean of its divisors is an integer number (4940711250609).

Almost surely, 29881422501217 is an apocalyptic number.

It is an amenable number.

9881422501217 is a deficient number, since it is larger than the sum of its proper divisors (1).

9881422501217 is an equidigital number, since it uses as much as digits as its factorization.

9881422501217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 645120, while the sum is 50.

The spelling of 9881422501217 in words is "nine trillion, eight hundred eighty-one billion, four hundred twenty-two million, five hundred one thousand, two hundred seventeen".