Base | Representation |
---|---|
bin | 11100110110000100000… |
… | …00010100010011110101 |
3 | 10111202012021111111110100 |
4 | 32123002000110103311 |
5 | 112214231404404143 |
6 | 2035145343344313 |
7 | 131414213254332 |
oct | 16330200242365 |
9 | 3452167444410 |
10 | 991097341173 |
11 | 35235a67a615 |
12 | 1400b85b2099 |
13 | 725c9a3aa94 |
14 | 35d7dd2d989 |
15 | 1aba9db66d3 |
hex | e6c20144f5 |
991097341173 has 12 divisors (see below), whose sum is σ = 1431603579328. Its totient is φ = 660723008040.
The previous prime is 991097341159. The next prime is 991097341207. The reversal of 991097341173 is 371143790199.
991097341173 is a `hidden beast` number, since 9 + 91 + 0 + 9 + 73 + 411 + 73 = 666.
It is not a de Polignac number, because 991097341173 - 212 = 991097337077 is a prime.
It is a super-2 number, since 2×9910973411732 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (991097341103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 65958 + ... + 1409448.
Almost surely, 2991097341173 is an apocalyptic number.
It is an amenable number.
991097341173 is a deficient number, since it is larger than the sum of its proper divisors (440506238155).
991097341173 is a wasteful number, since it uses less digits than its factorization.
991097341173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1425464 (or 1425461 counting only the distinct ones).
The product of its (nonzero) digits is 1285956, while the sum is 54.
The spelling of 991097341173 in words is "nine hundred ninety-one billion, ninety-seven million, three hundred forty-one thousand, one hundred seventy-three".
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