991134503483 has 2 divisors, whose sum is σ = 991134503484. Its totient is φ = 991134503482.

The previous prime is 991134503423. The next prime is 991134503533. The reversal of 991134503483 is 384305431199.

It is an a-pointer prime, because the next prime (991134503533) can be obtained adding 991134503483 to its sum of digits (50).

It is a strong prime.

It is an emirp because it is prime and its reverse (384305431199) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 991134503483 - 2¹⁰ = 991134502459 is a prime.

It is not a weakly prime, because it can be changed into another prime (991134503413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495567251741 + 495567251742.

It is an arithmetic number, because the mean of its divisors is an integer number (495567251742).

Almost surely, 2^991134503483 is an apocalyptic number.

991134503483 is a deficient number, since it is larger than the sum of its proper divisors (1).

991134503483 is an equidigital number, since it uses as much as digits as its factorization.

991134503483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1399680, while the sum is 50.

The spelling of 991134503483 in words is "nine hundred ninety-one billion, one hundred thirty-four million, five hundred three thousand, four hundred eighty-three".