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991134503533 is a prime number
BaseRepresentation
bin11100110110001000011…
…10000101001001101101
310111202021212102112122001
432123010032011021231
5112214320413103113
62035153152052301
7131415144163366
oct16330416051155
93452255375561
10991134503533
11352379652209
12140108b34091
137260464cb45
1435d84c44b6d
151abad2a77dd
hexe6c438526d

991134503533 has 2 divisors, whose sum is σ = 991134503534. Its totient is φ = 991134503532.

The previous prime is 991134503483. The next prime is 991134503551. The reversal of 991134503533 is 335305431199.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 918879450724 + 72255052809 = 958582^2 + 268803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-991134503533 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (991134507533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495567251766 + 495567251767.

It is an arithmetic number, because the mean of its divisors is an integer number (495567251767).

Almost surely, 2991134503533 is an apocalyptic number.

It is an amenable number.

991134503533 is a deficient number, since it is larger than the sum of its proper divisors (1).

991134503533 is an equidigital number, since it uses as much as digits as its factorization.

991134503533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 656100, while the sum is 46.

The spelling of 991134503533 in words is "nine hundred ninety-one billion, one hundred thirty-four million, five hundred three thousand, five hundred thirty-three".