Base | Representation |
---|---|
bin | 1001000001000000011101… |
… | …1111101000010100110111 |
3 | 1022002122221202111121222221 |
4 | 2100100013133220110313 |
5 | 2244403120011020234 |
6 | 33025532245303211 |
7 | 2042120104605415 |
oct | 220200737502467 |
9 | 38078852447887 |
10 | 9912910251319 |
11 | 3182050453909 |
12 | 1141231704b07 |
13 | 56ba2525605a |
14 | 263b049542b5 |
15 | 122cce32ceb4 |
hex | 904077e8537 |
9912910251319 has 2 divisors, whose sum is σ = 9912910251320. Its totient is φ = 9912910251318.
The previous prime is 9912910251317. The next prime is 9912910251331. The reversal of 9912910251319 is 9131520192199.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 9912910251319 - 21 = 9912910251317 is a prime.
It is a super-2 number, since 2×99129102513192 (a number of 27 digits) contains 22 as substring.
Together with 9912910251317, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9912910251311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4956455125659 + 4956455125660.
It is an arithmetic number, because the mean of its divisors is an integer number (4956455125660).
Almost surely, 29912910251319 is an apocalyptic number.
9912910251319 is a deficient number, since it is larger than the sum of its proper divisors (1).
9912910251319 is an equidigital number, since it uses as much as digits as its factorization.
9912910251319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 393660, while the sum is 52.
The spelling of 9912910251319 in words is "nine trillion, nine hundred twelve billion, nine hundred ten million, two hundred fifty-one thousand, three hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •