Base | Representation |
---|---|
bin | 101110001010011011… |
… | …0010110011000000011 |
3 | 100110212211011222211122 |
4 | 1130110312112120003 |
5 | 3111011303231210 |
6 | 113312550302455 |
7 | 10106430301325 |
oct | 1342466263003 |
9 | 313784158748 |
10 | 99134039555 |
11 | 39051643211 |
12 | 17267957a2b |
13 | 946b2a3905 |
14 | 4b26045615 |
15 | 28a31d3b55 |
hex | 1714d96603 |
99134039555 has 4 divisors (see below), whose sum is σ = 118960847472. Its totient is φ = 79307231640.
The previous prime is 99134039527. The next prime is 99134039593. The reversal of 99134039555 is 55593043199.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 99134039555 - 214 = 99134023171 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 99134039497 and 99134039506.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9913403951 + ... + 9913403960.
It is an arithmetic number, because the mean of its divisors is an integer number (29740211868).
Almost surely, 299134039555 is an apocalyptic number.
99134039555 is a deficient number, since it is larger than the sum of its proper divisors (19826807917).
99134039555 is a wasteful number, since it uses less digits than its factorization.
99134039555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19826807916.
The product of its (nonzero) digits is 3280500, while the sum is 53.
The spelling of 99134039555 in words is "ninety-nine billion, one hundred thirty-four million, thirty-nine thousand, five hundred fifty-five".
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