Search a number
-
+
992116254653 = 5314718667399
BaseRepresentation
bin11100110111111101011…
…11001010011110111101
310111211211021202122222122
432123332233022132331
5112223323230122103
62035434422252325
7131451365010506
oct16337657123675
93454737678878
10992116254653
11352832841377
121403418870a5
137272cb6a974
14360393a1bad
151ac19581b38
hexe6febca7bd

992116254653 has 4 divisors (see below), whose sum is σ = 992134975200. Its totient is φ = 992097534108.

The previous prime is 992116254643. The next prime is 992116254691. The reversal of 992116254653 is 356452611299.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 992116254653 - 220 = 992115206077 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 992116254595 and 992116254604.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (992116254643) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9280553 + ... + 9386846.

It is an arithmetic number, because the mean of its divisors is an integer number (248033743800).

Almost surely, 2992116254653 is an apocalyptic number.

It is an amenable number.

992116254653 is a deficient number, since it is larger than the sum of its proper divisors (18720547).

992116254653 is a wasteful number, since it uses less digits than its factorization.

992116254653 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18720546.

The product of its digits is 3499200, while the sum is 53.

The spelling of 992116254653 in words is "nine hundred ninety-two billion, one hundred sixteen million, two hundred fifty-four thousand, six hundred fifty-three".

Divisors: 1 53147 18667399 992116254653