992514137 has 2 divisors, whose sum is σ = 992514138. Its totient is φ = 992514136.

The previous prime is 992514113. The next prime is 992514139. The reversal of 992514137 is 731415299.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 805481161 + 187032976 = 28381^2 + 13676^2 .

It is a cyclic number.

It is not a de Polignac number, because 992514137 - 2¹⁰ = 992513113 is a prime.

Together with 992514139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 992514094 and 992514103.

It is not a weakly prime, because it can be changed into another prime (992514139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 496257068 + 496257069.

It is an arithmetic number, because the mean of its divisors is an integer number (496257069).

Almost surely, 2^992514137 is an apocalyptic number.

It is an amenable number.

992514137 is a deficient number, since it is larger than the sum of its proper divisors (1).

992514137 is an equidigital number, since it uses as much as digits as its factorization.

992514137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 68040, while the sum is 41.

The square root of 992514137 is about 31504.1923718098. The cubic root of 992514137 is about 997.4984598482.

The spelling of 992514137 in words is "nine hundred ninety-two million, five hundred fourteen thousand, one hundred thirty-seven".