Base | Representation |
---|---|
bin | 11100111001100110110… |
… | …10011000101110001110 |
3 | 10111221002212200121020112 |
4 | 32130303122120232032 |
5 | 112232131000003043 |
6 | 2040102232120022 |
7 | 131512315510640 |
oct | 16346332305616 |
9 | 3457085617215 |
10 | 993000000398 |
11 | 35314668165a |
12 | 140549836012 |
13 | 72840c92b43 |
14 | 360c08ca890 |
15 | 1ac6be4c518 |
hex | e733698b8e |
993000000398 has 8 divisors (see below), whose sum is σ = 1702285714992. Its totient is φ = 425571428736.
The previous prime is 993000000397. The next prime is 993000000439. The reversal of 993000000398 is 893000000399.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (993000000397) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35464285715 + ... + 35464285742.
It is an arithmetic number, because the mean of its divisors is an integer number (212785714374).
Almost surely, 2993000000398 is an apocalyptic number.
993000000398 is a deficient number, since it is larger than the sum of its proper divisors (709285714594).
993000000398 is a wasteful number, since it uses less digits than its factorization.
993000000398 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70928571466.
The product of its (nonzero) digits is 52488, while the sum is 41.
Subtracting from 993000000398 its reverse (893000000399), we obtain a palindrome (99999999999).
The spelling of 993000000398 in words is "nine hundred ninety-three billion, three hundred ninety-eight", and thus it is an aban number.
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