Base | Representation |
---|---|
bin | 11100111011011110001… |
… | …00111111001110101111 |
3 | 10112000200122021212100202 |
4 | 32131233010333032233 |
5 | 112241203230231134 |
6 | 2040345431344115 |
7 | 131546162203601 |
oct | 16355704771657 |
9 | 3460618255322 |
10 | 994001023919 |
11 | 35360a734422 |
12 | 140788b2203b |
13 | 7297049ab57 |
14 | 36177823171 |
15 | 1acc9c81d7e |
hex | e76f13f3af |
994001023919 has 2 divisors, whose sum is σ = 994001023920. Its totient is φ = 994001023918.
The previous prime is 994001023913. The next prime is 994001023921. The reversal of 994001023919 is 919320100499.
It is a strong prime.
It is an emirp because it is prime and its reverse (919320100499) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 994001023919 - 24 = 994001023903 is a prime.
It is a super-2 number, since 2×9940010239192 (a number of 25 digits) contains 22 as substring.
Together with 994001023921, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (994001023913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497000511959 + 497000511960.
It is an arithmetic number, because the mean of its divisors is an integer number (497000511960).
Almost surely, 2994001023919 is an apocalyptic number.
994001023919 is a deficient number, since it is larger than the sum of its proper divisors (1).
994001023919 is an equidigital number, since it uses as much as digits as its factorization.
994001023919 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 157464, while the sum is 47.
The spelling of 994001023919 in words is "nine hundred ninety-four billion, one million, twenty-three thousand, nine hundred nineteen".
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