Base | Representation |
---|---|
bin | 101110010100110000… |
… | …0011110000111011111 |
3 | 100111202222100101112222 |
4 | 1130221200132013133 |
5 | 3112214020010011 |
6 | 113411211015555 |
7 | 10121136236342 |
oct | 1345140360737 |
9 | 314688311488 |
10 | 99480625631 |
11 | 3920a246492 |
12 | 17343a3a5bb |
13 | 94c5032c2a |
14 | 4b5a0a4459 |
15 | 28c3845ddb |
hex | 172981e1df |
99480625631 has 2 divisors, whose sum is σ = 99480625632. Its totient is φ = 99480625630.
The previous prime is 99480625583. The next prime is 99480625633. The reversal of 99480625631 is 13652608499.
It is a strong prime.
It is an emirp because it is prime and its reverse (13652608499) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99480625631 - 26 = 99480625567 is a prime.
It is a super-2 number, since 2×994806256312 (a number of 23 digits) contains 22 as substring.
Together with 99480625633, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99480625633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49740312815 + 49740312816.
It is an arithmetic number, because the mean of its divisors is an integer number (49740312816).
Almost surely, 299480625631 is an apocalyptic number.
99480625631 is a deficient number, since it is larger than the sum of its proper divisors (1).
99480625631 is an equidigital number, since it uses as much as digits as its factorization.
99480625631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 53.
The spelling of 99480625631 in words is "ninety-nine billion, four hundred eighty million, six hundred twenty-five thousand, six hundred thirty-one".
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