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99480625631 is a prime number
BaseRepresentation
bin101110010100110000…
…0011110000111011111
3100111202222100101112222
41130221200132013133
53112214020010011
6113411211015555
710121136236342
oct1345140360737
9314688311488
1099480625631
113920a246492
1217343a3a5bb
1394c5032c2a
144b5a0a4459
1528c3845ddb
hex172981e1df

99480625631 has 2 divisors, whose sum is σ = 99480625632. Its totient is φ = 99480625630.

The previous prime is 99480625583. The next prime is 99480625633. The reversal of 99480625631 is 13652608499.

It is a strong prime.

It is an emirp because it is prime and its reverse (13652608499) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 99480625631 - 26 = 99480625567 is a prime.

It is a super-2 number, since 2×994806256312 (a number of 23 digits) contains 22 as substring.

Together with 99480625633, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (99480625633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49740312815 + 49740312816.

It is an arithmetic number, because the mean of its divisors is an integer number (49740312816).

Almost surely, 299480625631 is an apocalyptic number.

99480625631 is a deficient number, since it is larger than the sum of its proper divisors (1).

99480625631 is an equidigital number, since it uses as much as digits as its factorization.

99480625631 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 53.

The spelling of 99480625631 in words is "ninety-nine billion, four hundred eighty million, six hundred twenty-five thousand, six hundred thirty-one".