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995601951253103 is a prime number
BaseRepresentation
bin1110001001011111101010010…
…0101001000110001001101111
311211120010121122210112010222112
43202113322210221012021233
52020443420244010044403
613445245120003234235
7416464603321532045
oct34227724451061157
94746117583463875
10995601951253103
11269258464213a47
12937b63b307897b
133396bb26c5b04c
14137bd56a5c0395
157a17d58dcb9d8
hex3897ea4a4626f

995601951253103 has 2 divisors, whose sum is σ = 995601951253104. Its totient is φ = 995601951253102.

The previous prime is 995601951253057. The next prime is 995601951253111. The reversal of 995601951253103 is 301352159106599.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 995601951253103 - 212 = 995601951249007 is a prime.

It is a super-3 number, since 3×9956019512531033 (a number of 46 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (995601951253153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497800975626551 + 497800975626552.

It is an arithmetic number, because the mean of its divisors is an integer number (497800975626552).

Almost surely, 2995601951253103 is an apocalyptic number.

995601951253103 is a deficient number, since it is larger than the sum of its proper divisors (1).

995601951253103 is an equidigital number, since it uses as much as digits as its factorization.

995601951253103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9841500, while the sum is 59.

The spelling of 995601951253103 in words is "nine hundred ninety-five trillion, six hundred one billion, nine hundred fifty-one million, two hundred fifty-three thousand, one hundred three".