Base | Representation |
---|---|
bin | 1110001001011111101010010… |
… | …0101001000110001001101111 |
3 | 11211120010121122210112010222112 |
4 | 3202113322210221012021233 |
5 | 2020443420244010044403 |
6 | 13445245120003234235 |
7 | 416464603321532045 |
oct | 34227724451061157 |
9 | 4746117583463875 |
10 | 995601951253103 |
11 | 269258464213a47 |
12 | 937b63b307897b |
13 | 3396bb26c5b04c |
14 | 137bd56a5c0395 |
15 | 7a17d58dcb9d8 |
hex | 3897ea4a4626f |
995601951253103 has 2 divisors, whose sum is σ = 995601951253104. Its totient is φ = 995601951253102.
The previous prime is 995601951253057. The next prime is 995601951253111. The reversal of 995601951253103 is 301352159106599.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 995601951253103 - 212 = 995601951249007 is a prime.
It is a super-3 number, since 3×9956019512531033 (a number of 46 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (995601951253153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 497800975626551 + 497800975626552.
It is an arithmetic number, because the mean of its divisors is an integer number (497800975626552).
Almost surely, 2995601951253103 is an apocalyptic number.
995601951253103 is a deficient number, since it is larger than the sum of its proper divisors (1).
995601951253103 is an equidigital number, since it uses as much as digits as its factorization.
995601951253103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9841500, while the sum is 59.
The spelling of 995601951253103 in words is "nine hundred ninety-five trillion, six hundred one billion, nine hundred fifty-one million, two hundred fifty-three thousand, one hundred three".
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