9965097254863 has 2 divisors, whose sum is σ = 9965097254864. Its totient is φ = 9965097254862.

The previous prime is 9965097254843. The next prime is 9965097254881. The reversal of 9965097254863 is 3684527905699.

It is a strong prime.

It is an emirp because it is prime and its reverse (3684527905699) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9965097254863 - 2²⁹ = 9964560383951 is a prime.

It is a super-4 number, since 4×9965097254863⁴ (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9965097254843) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4982548627431 + 4982548627432.

It is an arithmetic number, because the mean of its divisors is an integer number (4982548627432).

Almost surely, 2^{9965097254863} is an apocalyptic number.

9965097254863 is a deficient number, since it is larger than the sum of its proper divisors (1).

9965097254863 is an equidigital number, since it uses as much as digits as its factorization.

9965097254863 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 881798400, while the sum is 73.

The spelling of 9965097254863 in words is "nine trillion, nine hundred sixty-five billion, ninety-seven million, two hundred fifty-four thousand, eight hundred sixty-three".