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9971492426263 is a prime number
BaseRepresentation
bin1001000100011010101101…
…0000111001001000010111
31022022021011110012110102001
42101012223100321020113
52301333104030120023
633112501304500131
72046262610100364
oct221065320711027
938267143173361
109971492426263
1131a4982577a25
12115066077a647
135744000332b4
142668a0db546b
151245ac3696ad
hex911ab439217

9971492426263 has 2 divisors, whose sum is σ = 9971492426264. Its totient is φ = 9971492426262.

The previous prime is 9971492426201. The next prime is 9971492426293. The reversal of 9971492426263 is 3626242941799.

It is a strong prime.

It is an emirp because it is prime and its reverse (3626242941799) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9971492426263 - 225 = 9971458871831 is a prime.

It is a super-2 number, since 2×99714924262632 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9971492426195 and 9971492426204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9971492426293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4985746213131 + 4985746213132.

It is an arithmetic number, because the mean of its divisors is an integer number (4985746213132).

Almost surely, 29971492426263 is an apocalyptic number.

9971492426263 is a deficient number, since it is larger than the sum of its proper divisors (1).

9971492426263 is an equidigital number, since it uses as much as digits as its factorization.

9971492426263 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 70543872, while the sum is 64.

The spelling of 9971492426263 in words is "nine trillion, nine hundred seventy-one billion, four hundred ninety-two million, four hundred twenty-six thousand, two hundred sixty-three".