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9971492426293 is a prime number
BaseRepresentation
bin1001000100011010101101…
…0000111001001000110101
31022022021011110012110110011
42101012223100321020311
52301333104030120133
633112501304500221
72046262610100436
oct221065320711065
938267143173404
109971492426293
1131a4982577a52
12115066077a671
13574400033308
142668a0db548d
151245ac3696cd
hex911ab439235

9971492426293 has 2 divisors, whose sum is σ = 9971492426294. Its totient is φ = 9971492426292.

The previous prime is 9971492426263. The next prime is 9971492426303. The reversal of 9971492426293 is 3926242941799.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9971492426289 + 4 = 3157767^2 + 2^2 .

It is a cyclic number.

It is not a de Polignac number, because 9971492426293 - 229 = 9970955555381 is a prime.

It is a super-2 number, since 2×99714924262932 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9971492426263) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4985746213146 + 4985746213147.

It is an arithmetic number, because the mean of its divisors is an integer number (4985746213147).

Almost surely, 29971492426293 is an apocalyptic number.

It is an amenable number.

9971492426293 is a deficient number, since it is larger than the sum of its proper divisors (1).

9971492426293 is an equidigital number, since it uses as much as digits as its factorization.

9971492426293 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 105815808, while the sum is 67.

The spelling of 9971492426293 in words is "nine trillion, nine hundred seventy-one billion, four hundred ninety-two million, four hundred twenty-six thousand, two hundred ninety-three".