99740010131 has 2 divisors, whose sum is σ = 99740010132. Its totient is φ = 99740010130.

The previous prime is 99740010101. The next prime is 99740010133. The reversal of 99740010131 is 13101004799.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 99740010131 - 2¹⁴ = 99739993747 is a prime.

It is a super-2 number, since 2×99740010131² (a number of 23 digits) contains 22 as substring.

Together with 99740010133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 99740010091 and 99740010100.

It is not a weakly prime, because it can be changed into another prime (99740010133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49870005065 + 49870005066.

It is an arithmetic number, because the mean of its divisors is an integer number (49870005066).

Almost surely, 2^99740010131 is an apocalyptic number.

99740010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

99740010131 is an equidigital number, since it uses as much as digits as its factorization.

99740010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6804, while the sum is 35.

The spelling of 99740010131 in words is "ninety-nine billion, seven hundred forty million, ten thousand, one hundred thirty-one".