9991000343 has 2 divisors, whose sum is σ = 9991000344. Its totient is φ = 9991000342.

The previous prime is 9991000319. The next prime is 9991000367. The reversal of 9991000343 is 3430001999.

It is a balanced prime because it is at equal distance from previous prime (9991000319) and next prime (9991000367).

It is a cyclic number.

It is not a de Polignac number, because 9991000343 - 2⁸ = 9991000087 is a prime.

It is a super-2 number, since 2×9991000343² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9991000297 and 9991000306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9991000303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4995500171 + 4995500172.

It is an arithmetic number, because the mean of its divisors is an integer number (4995500172).

Almost surely, 2^9991000343 is an apocalyptic number.

9991000343 is a deficient number, since it is larger than the sum of its proper divisors (1).

9991000343 is an equidigital number, since it uses as much as digits as its factorization.

9991000343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26244, while the sum is 38.

The square root of 9991000343 is about 99954.9915862134. The cubic root of 9991000343 is about 2153.7881902759.

The spelling of 9991000343 in words is "nine billion, nine hundred ninety-one million, three hundred forty-three", and thus it is an aban number.