Search a number
-
+
999113333311999 is a prime number
BaseRepresentation
bin1110001100101100000011001…
…1010100101000100111111111
311212000120022011001100122012001
43203023000303110220213333
52021423433101311440444
613500534155015123131
7420306361536550633
oct34313006324504777
94760508131318161
10999113333311999
1126a391648907464
1294082a359734a7
1333b64ca1a326b9
14138a14b4220dc3
157a7936d6108d4
hex38cb0335289ff

999113333311999 has 2 divisors, whose sum is σ = 999113333312000. Its totient is φ = 999113333311998.

The previous prime is 999113333311997. The next prime is 999113333312027.

999113333311999 is nontrivially palindromic in base 10.

It is a weak prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 999113333311999 - 21 = 999113333311997 is a prime.

It is a super-2 number, since 2×9991133333119992 (a number of 31 digits) contains 22 as substring.

Together with 999113333311997, it forms a pair of twin primes.

It is a zygodrome in base 10.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (999113333311997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 499556666655999 + 499556666656000.

It is an arithmetic number, because the mean of its divisors is an integer number (499556666656000).

Almost surely, 2999113333311999 is an apocalyptic number.

999113333311999 is a deficient number, since it is larger than the sum of its proper divisors (1).

999113333311999 is an equidigital number, since it uses as much as digits as its factorization.

999113333311999 is an evil number, because the sum of its binary digits is even.

The product of its digits is 129140163, while the sum is 73.

The spelling of 999113333311999 in words is "nine hundred ninety-nine trillion, one hundred thirteen billion, three hundred thirty-three million, three hundred eleven thousand, nine hundred ninety-nine".