9993000341 has 2 divisors, whose sum is σ = 9993000342. Its totient is φ = 9993000340.

The previous prime is 9993000323. The next prime is 9993000343. The reversal of 9993000341 is 1430003999.

9993000341 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9156576100 + 836424241 = 95690^2 + 28921^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-9993000341 is a prime.

It is a super-2 number, since 2×9993000341² (a number of 21 digits) contains 22 as substring.

Together with 9993000343, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 9993000295 and 9993000304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9993000343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4996500170 + 4996500171.

It is an arithmetic number, because the mean of its divisors is an integer number (4996500171).

Almost surely, 2^9993000341 is an apocalyptic number.

It is an amenable number.

9993000341 is a deficient number, since it is larger than the sum of its proper divisors (1).

9993000341 is an equidigital number, since it uses as much as digits as its factorization.

9993000341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26244, while the sum is 38.

The square root of 9993000341 is about 99964.9955784524. The cubic root of 9993000341 is about 2153.9318957617.

The spelling of 9993000341 in words is "nine billion, nine hundred ninety-three million, three hundred forty-one", and thus it is an aban number.